What is the length of time to complete a door assembly on an automobile factory?
FeFe asked:
The length of time to complete a door assembly on an automobile factory assembly line is normally distributed with a mean MU=7.9 minutes and standard deviation ? = 1.9 minutes. For a door selected at random, what is the probability the assembly line time will be
The length of time to complete a door assembly on an automobile factory assembly line is normally distributed with a mean MU=7.9 minutes and standard deviation ? = 1.9 minutes. For a door selected at random, what is the probability the assembly line time will be
a.) 7 minutes or less?
b.) 10 minutes or less?
c.) between 7 and 10 minutes?
Please explain and Thank you so much!
A) P(T 7) = P(Z (7-7.9)/1.9)
P( Z -.4736842105)
Area below Z(-.4736842105) = .317863 = probability.
B) P(T 10) P(Z (10-7.9)/1.9)
P( Z 1.105263158)
Area below Z(1.105263158) = .865477 = probability.
C) Between 7 and 10 minutes = P(10) – P(7)
= .865477 – .317863 = 0.547614
For the time will be min or less we can plug those in and 19 so we are given m79 and 19 so we are given m79 and 19 so we integrate from to which gives us 0865 0318 0548.
The time will be min or less we are given m79 and 19 so we can plug those in and 19 so we can plug those in.